Question

tìm x

x-1/3 +3x-5/2 +2x/9 + -5x +3 /9 =210/420

Answer 1

\(\dfrac{x-1}{3}\)+\(\dfrac{3x-5}{2}+\dfrac{2x}{9}+\dfrac{-5x+3}{9}=\dfrac{210}{420}\)

\(\Leftrightarrow\)\(\dfrac{x-1}{3}+\dfrac{3x-5}{2}\)\(+\dfrac{-3x+3}{9}\)\(=\dfrac{1}{2}\)

\(\Leftrightarrow\dfrac{6\left(x-1\right)}{18}+\dfrac{9\left(3x-5\right)}{18}\)\(+\dfrac{2\left(-3x+3\right)}{18}=\dfrac{9}{18}\)

\(\Rightarrow\)\(6x-6+27x-45-6x+6=9\)

\(\Leftrightarrow\)\(6x+27x-6x=9+6+45-6\)

\(\Leftrightarrow27x=54\)

\(\Rightarrow\)\(x=2\)