Question

(X-3)¹⁰⁰-1=0

(9-5x)²⁰¹⁹+1=0

(4x-3)⁵=(2-x)⁵

(2x-9)²=(5x-6)²

(11-4x)⁶-(2-5x)⁶

Answer 1

a) (x-3)¹⁰⁰-1=0

\(\Leftrightarrow\left(x-3\right)^{100}=0+1=1\)

\(\Leftrightarrow\left(x-3\right)^{100}=1^{100}=\left(-1\right)^{100}\)

\(\Rightarrow\left[{}\begin{matrix}x-3=1\\x-3=-1\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=1+3=4\\x=\left(-1\right)+3=2\end{matrix}\right.\)

Vậy: x\(\in\left\{4;2\right\}\)

b) (9-5x)²⁰¹⁹+1=0

\(\Leftrightarrow\left(9-5x\right)^{2019}=0-1=-1=\left(-1\right)^{2019}\)

\(\Rightarrow9-5x=-1\)

\(\Leftrightarrow5x=9-\left(-1\right)=10\)

\(\Leftrightarrow x=10:5=2\)

Vậy: x=2