Question

Tìm x trong các tỉ lệ thức sau :

a) \(\frac{x}{7}=\frac{18}{14}\)

b)\(6:x=1\frac{3}{4}:5\)

c) 5,7:0,35 = (-x ) : 0,45

Help me 

Answer 1

a) \(\frac{x}{7}=\frac{18}{14}\)

\(\Rightarrow\frac{x}{7}=\frac{9}{7}\)

\(\Rightarrow x=7\)

Vậy x=7

b)\(6:x=1\frac{3}{4}:5\)

\(\frac{6}{x}=\frac{7}{4}:5\)

\(\frac{6}{x}=\frac{7}{20}\)

\(\Rightarrow6.20=7x\)

\(\Rightarrow120=7.x\)

\(\Rightarrow x=\frac{120}{7}\)

Vậy \(x=\frac{120}{7}\)

 

Answer 2

a) Ta có :

\(x\)/7 = 18/14

=> \(x\) = (7 x 18)/14

x= 9

b) Ta có:

6 : \(x\)= 1(3/4) : 5

=> \(x\)= (6 x 5)/1(3/4)

= \(\frac{30}{\frac{7}{4}}\)

c) Ta có:

5,7 : 0,35 = -\(x\):0,45

=> -\(x\)= (5,7 x 0,45)/ 0,35

\(x\)=5130/7