Question

Tìm x thuộc Z để \(\frac{\sqrt{x}+1}{\sqrt{x}-3}\)thuộc Z

Answer 1

Để \(\frac{\sqrt{x}+1}{\sqrt{x}-3}\in Z\Leftrightarrow\frac{\sqrt{x}-3+4}{\sqrt{x}-3}\in Z\)

\(\Leftrightarrow\frac{\sqrt{x}-3}{\sqrt{x}-3}+\frac{4}{\sqrt{x}-3}\in Z\Leftrightarrow1+\frac{4}{\sqrt{x}-3}\in Z\)

\(\Leftrightarrow\frac{4}{\sqrt{x}-3}\in Z\Rightarrow\sqrt{x}-3\inƯ\left(4\right)\in\left\{-1;1;-2;2;-4;4\right\}\)

\(\Leftrightarrow\sqrt{x}\in\left\{2;4;1;5;-1;7\right\}\Rightarrow x\left\{4;16;1;25;1;49\right\}\)

Vậy \(x=\left\{1;4;16;25;49\right\}\)thì \(\frac{\sqrt{x}+1}{\sqrt{x}-3}\in Z.\)