Giải:
\(3x^2-6=0\)
\(\Leftrightarrow3\left(x^2-2\right)=0\)
\(\Leftrightarrow x^2-2=0\)
\(\Leftrightarrow x^2=2\)
\(\Leftrightarrow x=\pm\sqrt{2}\)
Vậy ...
\(3x^2-6=0\)
<=>\(3\left(x^2-2\right)=0\)
<=>\(x^2-2=0\)
<=>\(x^2=2\)
<=>\(x=\sqrt{2}\)
<=>\(x=-\sqrt{2}\)
=> Kết luận: Vậy...