\(x^{20}-x^{18}=0\)
\(\Rightarrow x^{18}\left(x^2-1\right)=0\)
\(\Rightarrow\left[\begin{matrix}x^{18}=0\\x^2-1=0\end{matrix}\right.\)
\(\Rightarrow\left[\begin{matrix}x=0\\x^2=1\end{matrix}\right.\)\(\Rightarrow\left[\begin{matrix}x=0\\x=1\\x=-1\end{matrix}\right.\)
x20 - x18 = 0
=> x20 = x18
Mà 120 = 118 hoặc 020 = 018
=> x thuộc {0;1}
xin lỗi, thiếu tg đề bài là nguyên dương
x^20-x^18=0
=> x^20=x^18
=>x^18.x^2=x^18.1
hoac x^18.x^2=x^18
+)x^18.x^2=x^18.1
=>x^2=1
=>x=1
+)x^18.x^2=x^18
=>x^2=0
=>x=0
Vay x=0 hoac x=1