Question

tim x 

\(\frac{1}{6}x+\frac{1}{10}x-\frac{4}{15}x+1=0\)

Answer 1

\(\frac{1}{6}x+\frac{1}{10}x-\frac{4}{15}x+1=0\)

\(\Rightarrow x\left(\frac{1}{6}+\frac{1}{10}-\frac{4}{15}\right)+1=0\)

\(\Rightarrow x.0+1=0\)

=> 1=0 ( Vô lý )

Vậy \(x\in\varnothing\)

Answer 2

\(\frac{1}{6}x+\frac{1}{10}x-\frac{4}{15}x+1=0\)

\(\Rightarrow x.\left(\frac{1}{6}+\frac{1}{10}-\frac{4}{15}\right)=1\)

\(\Rightarrow x.0=1\Rightarrow x=0\)

Vậy x=0