Question

Tìm x :

\(\dfrac{x-1}{4}=\dfrac{2}{\left(x-1\right)^2}\)

Answer 1

\(\dfrac{x-1}{4}=\dfrac{2}{\left(x-1\right)^2}\)

\(\Rightarrow\left(x-1\right)^3=2.4=8\)

\(\Rightarrow x-1=2\Rightarrow x=3\)

Answer 2

\(\dfrac{x-1}{4}=\dfrac{2}{\left(x-1\right)^2}\)

=> ( x - 1)³ = 2.4 = 8

=>( x - 1 )³ = 2

=> x=3

Answer 3

\(\dfrac{x-1}{4}=\dfrac{2}{\left(x-1\right)^2}\)

\(\Leftrightarrow\left(x-1\right).\left(x-1\right)^2=4.2\)

\(\Rightarrow\left(x-1\right)^3=8=2^3\)

\(\Rightarrow x-1=2\)

\(\Rightarrow x=3\)

Vậy...