Câu hỏi của Trần Duy Quân

Question

Tìm x .

$\dfrac{\dfrac{1}{2}}{-x}=\dfrac{x}{-200}$

thám tử · Accepted Answer

$\dfrac{\dfrac{1}{2}}{-x}=\dfrac{x}{-200}$

$\Leftrightarrow\dfrac{\dfrac{1}{2}}{-x}=\dfrac{-x}{200}$

$\Leftrightarrow\left(-x\right).\left(-x\right)=\dfrac{1}{2}.200$

$\Rightarrow x^2=100=\left(\pm10\right)^2$

$\Rightarrow x=\pm10$

Vậy...........Câu trả lời: $\dfrac{\dfrac{1}{2}}{-x}=\dfrac{x}{-200}$

$\Leftrightarrow\dfrac{\dfrac{1}{2}}{-x}=\dfrac{-x}{200}$

$\Leftrightarrow\left(-x\right).\left(-x\right)=\dfrac{1}{2}.200$

$\Rightarrow x^2=100=\left(\pm10\right)^2$

$\Rightarrow x=\pm10$

Vậy...........

hùng Lý tiểu · Answer

-10Câu trả lời: -10

Phạm Tiến · Answer

$\dfrac{1}{2}.\left(-200\right)=-x.x$

$-100=-\left(x^2\right)$

$100=x^2$

$x=10$Câu trả lời: $\dfrac{1}{2}.\left(-200\right)=-x.x$

$-100=-\left(x^2\right)$

$100=x^2$

$x=10$

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