\(\dfrac{4}{3}+x.\dfrac{2}{3}-\dfrac{1}{4}=4\dfrac{5}{12}\)
<=> \(\dfrac{13}{12}+x.\dfrac{2}{3}=\dfrac{53}{12}\)
<=> \(x.\dfrac{2}{3}=\dfrac{10}{3}\)
<=> x = 5
@Hoàng Mạnh Quân
1. Tìm X
a, \(\left(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}\right)\cdot10-x=0\)
b, \(\left(\dfrac{1}{11}-\dfrac{1}{21}\right)\cdot462-2.04:\left(x+1.5\right)+11.02=30\)
c, \(\dfrac{4}{3}+x\cdot\dfrac{2}{3}-\dfrac{1}{4}=4\dfrac{5}{12}\)
Thực hiện phép tính bằng cách hợp lí :
\(B=1\dfrac{6}{41}\cdot\left(\dfrac{12+\dfrac{12}{9}-\dfrac{12}{37}-\dfrac{12}{53}}{3+\dfrac{1}{3}-\dfrac{3}{37}-\dfrac{3}{53}}:\dfrac{4+\dfrac{4}{17}+\dfrac{4}{19}+\dfrac{4}{2006}}{5+\dfrac{5}{17}+\dfrac{5}{19}+\dfrac{5}{2006}}\right)\cdot\dfrac{124242423}{237373735}\)
Tìm x
a ) \(15-3\cdot x=6\) b)\(\dfrac{2}{3}-\dfrac{4}{3}\cdot x=\dfrac{1}{2}\) c) \(3^{19}\cdot\left(x-12\right)=4\cdot3^{20}\) d) \(3\cdot\left(x-4\right)=2^2\cdot3^3\)
1. Tìm X
a, \(\left(\dfrac{1}{11}-\dfrac{1}{21}\right)\cdot462-2,04:\left(x+1,5\right)+11,02=30\)
b,
\(\dfrac{-5}{9}+1\dfrac{5}{9}\cdot\left(\dfrac{3}{4}-\dfrac{2}{5}\right):7^2\)
\(1\dfrac{13}{15}\cdot0,75-\left(\dfrac{104}{195}+25\%\right)\cdot\dfrac{24}{47}-3\dfrac{12}{13}:3\)
\(1\dfrac{13}{15}\cdot\left(0,5\right)^2\cdot3+\left(\dfrac{8}{15}+1\dfrac{19}{60}\right):1\dfrac{23}{24}\)
tìm x:
a)\(\left(x+\dfrac{1}{2}\right).\left(\dfrac{2}{3}-2x\right)=0\)
b) \(\left(x.6\dfrac{2}{7}+\dfrac{3}{7}\right).2\dfrac{1}{5}-\dfrac{3}{7}=-2\)
c) \(x.3\dfrac{1}{4}+\left(\dfrac{-7}{6}\right).x-1\dfrac{2}{3}=\dfrac{5}{12}\)
d) \(5\dfrac{8}{17}:x+\left(-\dfrac{4}{17}\right):x+3\dfrac{1}{7}:17\dfrac{1}{3}=\dfrac{4}{11}\)
Tính nhanh
\(4\dfrac{8}{15}-5\dfrac{7}{12}-0\dfrac{1}{15}\)
Tính
\(\dfrac{-3}{5}-\dfrac{4}{5}\cdot\dfrac{10}{3}\)
tìm x
\([\dfrac{6:\dfrac{3}{5}-1\dfrac{1}{16}.\dfrac{16}{7}}{4\dfrac{1}{5}-\dfrac{10}{11}+5\dfrac{2}{11}}-\dfrac{\left(\dfrac{3}{20}+\dfrac{1}{2}-\dfrac{1}{5}\right).\dfrac{12}{49}}{3\dfrac{1}{3}+\dfrac{2}{9}}].x=2\dfrac{23}{96}\)
1. Tìm x, biết
a. \(\dfrac{1}{2}x-\dfrac{3}{4}x-\dfrac{7}{3}=\dfrac{-5}{6}\)
b. \(Ix-\dfrac{1}{6}I+\dfrac{-5}{12}=\dfrac{4}{7}.\dfrac{14}{48}\)
