\(\dfrac{2}{3}-\dfrac{1}{2}x=\dfrac{5}{6}\)
\(\Leftrightarrow\dfrac{1}{2}x=\dfrac{2}{3}-\dfrac{5}{6}\)
\(\Leftrightarrow\dfrac{1}{2}x=\dfrac{-1}{6}\)
\(\Rightarrow x=\dfrac{-1}{6}:\dfrac{1}{2}=\dfrac{-1}{3}\)
\(\dfrac{2}{3}-\dfrac{1}{2}x=\dfrac{5}{6}\)
\(\Leftrightarrow\dfrac{1}{2}x=\dfrac{2}{3}-\dfrac{5}{6}\)
\(\Leftrightarrow\dfrac{1}{2}x=\dfrac{-1}{6}\)
\(\Rightarrow x=\dfrac{-1}{6}:\dfrac{1}{2}=\dfrac{-1}{3}\)
1,\(\dfrac{3}{16}\)- ( x - \(\dfrac{5}{4}\) ) - ( \(\dfrac{3}{4}\) + \(\dfrac{-7}{8}\) - 1 ) = \(2\dfrac{1}{2}\)
2,\(\dfrac{1}{2}\) . ( \(\dfrac{1}{6}\) - \(\dfrac{9}{10}\) ) = \(\dfrac{1}{5}\) - x + ( \(\dfrac{1}{15}\) - \(\dfrac{-1}{5}\) )
Giúp mik nhanh với ạ
a)\(\dfrac{\left(x+\dfrac{3}{4}\right)\cdot\dfrac{7}{2}-\dfrac{1}{6}}{-\left(\dfrac{4}{5}+\dfrac{1}{3}\right)\cdot\dfrac{1}{2}+1}=2\dfrac{33}{52}\)
b)\(\dfrac{\left(5-\dfrac{2}{7}\right)\cdot\dfrac{7}{9}:\dfrac{3}{5}}{\left(3x-\dfrac{5}{6}\right):\dfrac{1}{7}}=5\dfrac{5}{21}\)
Bài 7: Tìm X
a) \(\dfrac{\left(x+\dfrac{3}{4}\right)\cdot\dfrac{7}{2}-\dfrac{1}{6}}{-\left(\dfrac{4}{5}+\dfrac{1}{3}\right)\cdot\dfrac{1}{2}+1}=2\dfrac{33}{52}\)
b)\(\dfrac{\left(5-\dfrac{2}{7}\right)\cdot\dfrac{7}{9}\cdot\dfrac{3}{5}}{\left(3x-\dfrac{5}{6}\right):\dfrac{1}{7}}=5\dfrac{5}{21}\)
BT1: Tìm x, biết:
6) \(\dfrac{1}{2}.\left(\dfrac{1}{3}x-\dfrac{1}{5}\right)^2-\dfrac{1}{5}=-\dfrac{3}{40}\)
\(\dfrac{4}{9}.19\dfrac{1}{3}+\dfrac{-4}{9}.39\dfrac{1}{3}+\dfrac{-3^2}{5}:\left(-0,2\right)\)
\(\dfrac{\left(-5^3\right)^2}{27}.\dfrac{3}{23}.\dfrac{6^2}{-5^6}\)
\(1\dfrac{4}{23}+\dfrac{5}{21}-\dfrac{4}{23}+0,5+\dfrac{16}{21}\)
\(\dfrac{3}{7}.19\dfrac{1}{3}-\dfrac{3}{7}:33\dfrac{1}{3}\)
\(\dfrac{3}{4}-\left(x+\dfrac{1}{2}\right)=\dfrac{4}{5}\)
x:(-2,14)=(-3,12):1,2
tìm x biết
a) \(\dfrac{1}{2}x+2\dfrac{1}{2}=3\dfrac{1}{2}x-\dfrac{3}{4}\)
b) \(\dfrac{2}{3}x-\dfrac{2}{5}=\dfrac{1}{2}x-\dfrac{1}{3}\)
c) \(\dfrac{1}{3}x+\dfrac{2}{5}\left(x+1\right)=0\)
d) \(\dfrac{2}{3}-\dfrac{1}{3}\left(x-\dfrac{3}{2}\right)-\dfrac{1}{2}\left(2x+1\right)=5\)
e) \(\dfrac{x+2015}{5}+\dfrac{x+2016}{4}=\dfrac{x+2017}{3}+\dfrac{x+2018}{2}\)
\(\left|x+\dfrac{1}{2}\right|=\dfrac{1}{2}\)
\(\dfrac{2}{3}-\dfrac{1}{2}x=\dfrac{5}{6}\)
Tìm x:
3\(\dfrac{1}{14}\) - 5\(\dfrac{1}{3}\) - \(\dfrac{4}{7}\) + \(\dfrac{11}{21}\) = x -\(\dfrac{1}{2}\)
Làm ra bài giải giúp mk vs
\(\left(3\dfrac{1}{2}x-3\right)-\left(\dfrac{2}{3}x-1\right)+\left(-\dfrac{5}{6}x-2\right)=-3\)
Tìm x , biết
a) \(\left|x-4\right|=6\)
b) \(\dfrac{x}{5}=\dfrac{9}{7}\)
c) \(1\dfrac{2}{5}x+\dfrac{3}{7}=\dfrac{-4}{5}\)
d) \(\left|x+\dfrac{2}{3}\right|+2=2\dfrac{1}{3}\)