Question

Tìm x:\(-\dfrac{22}{15}\)x + \(\dfrac{1}{3}\) = | \(-\dfrac{2}{3}\) + \(\dfrac{1}{5}\)|

Answer 1

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\(\text{−}\dfrac{22}{15}x+\dfrac{1}{3}=\left|\text{−}\dfrac{2}{3}+\dfrac{1}{5}\right|\)

\(\text{−}\dfrac{22}{15}x+\dfrac{1}{3}=\dfrac{7}{15}\)

\(\text{−}\dfrac{22}{15}x=\dfrac{2}{15}\)

\(x=\text{−}\dfrac{1}{11}\)

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Answer 2

\(-\dfrac{22}{15}x+\dfrac{1}{3}=\left|-\dfrac{2}{3}+\dfrac{1}{5}\right|\)

\(\Rightarrow-\dfrac{22}{15}x+\dfrac{1}{3}=-\dfrac{7}{15}\Rightarrow-\dfrac{22}{15}x=-\dfrac{4}{5}\)

\(\Rightarrow x=\dfrac{6}{11}\)

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Answer 3

\(\text{−}\dfrac{22}{15}x+\dfrac{1}{3}=\left|\text{−}\dfrac{2}{3}+\dfrac{1}{5}\right|\)

\(\text{−}\dfrac{22}{15}x+\dfrac{1}{3}=\dfrac{7}{15}\)

\(\text{−}\dfrac{22}{15}x=\dfrac{2}{15}\)

\(x=\text{−}\dfrac{1}{11}\)

Vậy ...