Tìm x, biết:
a)−\(\dfrac{3}{5}\).x=\(\dfrac{12}{25}\);
b)\(\dfrac{3}{5}\)x−\(\dfrac{3}{4}\)=−1\(\dfrac{1}{2}\);
c)\(\dfrac{2}{5}\)+\(\dfrac{3}{5}\):x=0,5;
d)\(\dfrac{3}{4}\)−(x−\(\dfrac{1}{2}\))=1\(\dfrac{2}{3}\)
e)2\(\dfrac{2}{15}\):(\(\dfrac{1}{3}\)−5x)=−2\(\dfrac{2}{5}\)
g)x2+\(\dfrac{1}{9}\)=\(\dfrac{5}{3}\):3.
a)
\(-\dfrac{3}{5}.x=\dfrac{12}{25}\)
\(x=\dfrac{12}{25}:\left(-\dfrac{3}{5}\right)\)
\(x=\dfrac{12}{25}.\dfrac{-5}{3}\)
\(x=\dfrac{-4}{5}\)
b)
\(\dfrac{3}{5}x-\dfrac{3}{4}=-1\dfrac{1}{2}\)
\(\dfrac{3}{5}x-\dfrac{3}{4}=\dfrac{-3}{2}\)
\(\dfrac{3}{5}x=\dfrac{-3}{2}+\dfrac{3}{4}\)
\(\dfrac{3}{5}x=\dfrac{-6}{4}+\dfrac{3}{4}\)
\(\dfrac{3}{5}x=\dfrac{-3}{4}\)
\(x=\dfrac{-3}{4}:\dfrac{3}{5}\)
\(x=\dfrac{-3}{4}.\dfrac{5}{3}\)
\(x=\dfrac{-5}{4}\)
c)
\(\dfrac{2}{5}+\dfrac{3}{5}:x=0,5\)
\(\dfrac{2}{5}+\dfrac{3}{5}:x=\dfrac{1}{2}\)
\(\dfrac{3}{5}:x=\dfrac{1}{2}-\dfrac{2}{5}\)
\(\dfrac{3}{5}:x=\dfrac{5}{10}-\dfrac{4}{10}\)
\(\dfrac{3}{5}:x=\dfrac{1}{10}\)
\(x=\dfrac{3}{5}:\dfrac{1}{10}\)
\(x=\dfrac{3}{5}.\dfrac{10}{1}\)
\(x=6\)
d)
\(\dfrac{3}{4}-\left(x-\dfrac{1}{2}\right)=1\dfrac{2}{3}\)
\(\dfrac{3}{4}-\left(x-\dfrac{1}{2}\right)=\dfrac{5}{3}\)
\(x-\dfrac{1}{2}=\dfrac{3}{4}-\dfrac{5}{3}\)
\(x-\dfrac{1}{2}=\dfrac{9}{12}-\dfrac{20}{12}\)
\(x-\dfrac{1}{2}=\dfrac{-11}{12}\)
\(x=\dfrac{-11}{12}+\dfrac{1}{2}\)
\(x=\dfrac{-11}{12}+\dfrac{6}{12}\)
\(x=\dfrac{-5}{12}\)
e)
\(2\dfrac{2}{15}:\left(\dfrac{1}{3}-5x\right)=-2\dfrac{2}{5}\)
\(\dfrac{32}{15}:\left(\dfrac{1}{3}-5x\right)=\dfrac{-12}{5}\)
\(\dfrac{1}{3}-5x=\dfrac{32}{15}:\dfrac{-12}{5}\)
\(\dfrac{1}{3}-5x=\dfrac{32}{15}.\dfrac{-5}{12}\)
\(\dfrac{1}{3}-5x=\dfrac{-8}{9}\)
\(5x=\dfrac{1}{3}-\dfrac{-8}{9}\)
\(5x=\dfrac{3}{9}+\dfrac{8}{9}\)
\(5x=\dfrac{11}{9}\)
\(x=\dfrac{11}{9}:5\)
\(x=\dfrac{11}{45}\)
g)
\(x^2+\dfrac{1}{9}=\dfrac{5}{3}:3\)
\(x^2+\dfrac{1}{9}=\dfrac{5}{9}\)
\(x^2=\dfrac{5}{9}-\dfrac{1}{9}\)
\(x^2=\dfrac{4}{9}\)
\(x^2=\left(\dfrac{2}{3}\right)^2\) hoặc \(x^2=\left(-\dfrac{2}{3}\right)^2\)
Nên \(\Rightarrow x=\dfrac{2}{3}\) hoặc \(x=-\dfrac{2}{3}\)
a) x=−35−35
x=3535x=3434
−34−34
x=3535
x=3535:x=0,5-3535:x=3535:1212)=2323
(x-3434-11212)=−1112−1112+−1712−1712
e) 215215:(-21313-5x=1313-119119
x=11451145
g) x2+5959
x2=1919
x2=√4949
x=