\(\left(x-4\right)^2-36=0\)
\(\Leftrightarrow\left(x-4\right)^2=0+36\)
\(\Leftrightarrow\left(x-4\right)^2=36\)
\(\Leftrightarrow\left(x-4\right)^2=\pm\sqrt{36}\)
\(\Leftrightarrow\left(x-4\right)=\pm6\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x-4=6\\x-4=-6\end{array}\right.\Leftrightarrow\left[\begin{array}{nghiempt}x=10\\x=-2\end{array}\right.\)
Vậy \(x\in\left\{10;-2\right\}\)
Đúng 0
Bình luận (1)
( x - 4)2 = 36
( x - 4)2 = 62
x - 4 = 6
x = 10
Đúng 0
Bình luận (0)
