Question

tìm x, biết:

a. \(\frac{5}{7}\) x + 0,125= \(\frac{9}{8}\)                                                                b.x+ \(\frac{7}{12}\) = \(\frac{1}{3}\) - \(\frac{5}{6}\)

c.( \(\frac{202}{909}\) + \(\frac{333}{444}\) ) .x = \(\frac{35}{36}\)

Answer 1

a) \(\frac{5}{7}x+0,125=\frac{9}{8}\)

\(\frac{5}{7}x=\frac{9}{8}-0,125\)

\(\frac{5}{7}x=\frac{9}{8}-\frac{1}{8}\)

\(\frac{5}{7}x=1\)

\(x=1:\frac{5}{7}\)

\(x=\frac{7}{5}\)

b) \(x+\frac{7}{12}=\frac{1}{3}-\frac{5}{6}\)

\(x+\frac{7}{12}=-\frac{1}{2}\)

\(x=-\frac{1}{2}-\frac{7}{12}\)

\(x=-\frac{13}{12}\)

Answer 2

c) \(\left(\frac{202}{909}+\frac{333}{444}\right).x=\frac{35}{36}\)

\(\frac{35}{36}x=\frac{35}{36}\)

\(x=\frac{35}{36}:\frac{35}{36}\)

\(x=1\)