Question

Tìm x biết:

Answer 1

\(a.x+9=2\frac{1}{3}\)

    \(x=2\frac{1}{3}-9\)

    \(x=-\frac{20}{3}\)

\(b.\frac{-5}{2}.x=\frac{1}{10}\)

     \(x=\frac{1}{10}:\frac{-5}{2}\)

     \(x=-\frac{1}{25}\)

Answer 2

a)

<=> x=\(\frac{7}{3}-9=-\frac{20}{3}\)

b)

<=> x=\(\frac{1}{10}:\frac{-5}{2}=-\frac{2}{25}\)

Answer 3

\(a,x+9=2\dfrac{1}{3}\)

x +9 =\(\dfrac{7}{3}\)

x =\(\dfrac{7}{3}-9\)

x =\(\dfrac{-20}{3}\)

b,\(\dfrac{-5}{2}.x=\dfrac{1}{10}\)

\(x=\dfrac{1}{10}:\dfrac{-5}{2}\)

\(x=\dfrac{-1}{25}\)

Answer 4

x+9=2\(\dfrac{1}{3}\)

x+9=\(\dfrac{7}{3}\)

x =\(\dfrac{7}{3}-9\)

x =\(\dfrac{-20}{3}\)

b.\(\dfrac{-5}{2}x=\dfrac{1}{10}\)

\(x=\dfrac{1}{10}:\dfrac{-5}{2}\)

\(x=\dfrac{-1}{25}\)

Answer 5

a. x + 9 = \(2\dfrac{1}{3}\) b. \(\dfrac{-5}{2}\). x = \(\dfrac{1}{10}\)

\(\Rightarrow\) x + 9 = \(\dfrac{7}{3}\) \(\Rightarrow\) x = \(\dfrac{1}{10}\) : \(\dfrac{-5}{2}\)

\(\Rightarrow\) x = \(\dfrac{7}{3}-9\) \(\Rightarrow\) x = \(\dfrac{1}{10}\) . \(\dfrac{-2}{5}\)

\(\Rightarrow\) x = \(\dfrac{-20}{3}\) \(\Rightarrow\) x = \(\dfrac{-1}{25}\)