\(x+\dfrac{1}{2}=\dfrac{3}{5}\)
\(x=\dfrac{3}{5}-\dfrac{1}{2}\)
\(x=\dfrac{6}{10}-\dfrac{5}{10}\)
\(x=\dfrac{1}{10}\)
\(x+\dfrac{1}{2}-\dfrac{3}{5}\)
\(x=\dfrac{3}{5}-\dfrac{1}{2}\)
\(x=\dfrac{6}{10}-\dfrac{5}{10}\)
\(x=\dfrac{1}{10}\)
`x+1/2=3/5`
`=>x=3/5-1/2`
`=>x=6/10-5/10`
`=>x=1/10`
Vậy `x=1/10`
\(x+\dfrac{1}{2}=\dfrac{3}{5}\\ x=\dfrac{3}{5}-\dfrac{1}{2}\\ x=\dfrac{1}{10}\)
\(x+\dfrac{1}{2}=\dfrac{3}{5}\)
\(x=\dfrac{3}{5}-\dfrac{1}{2}\)
\(x=\dfrac{6}{10}-\dfrac{5}{10}\)
\(x=\dfrac{1}{10}\)
#Sahara |
`x + 1/2 = 3/5 `
` x = 3/5 -1/2`
` x = 6/10 -5/10`
`x = 1/10`
Vậy `x=1/10`
x + 1/2 = 3/5
x = 3/5 - 1/2
x = 6/10 - 5/10
x = 1/10