Do x+4 và x+2 là 2 kết quả khác nhau
=> \(\left(x+4\right)^{10}\ge\left(x+2\right)^8\)
Dấu "=" xảy ra khi : \(x+4=x+2=0\) (loại) ;
\(\left(x+4\right)^{10}=\left(x+2\right)^8=1\)
Mà \(x+4>x+2\)
=>x+4 = 1; x+2=-1
=>x=-3
CHÚC BẠN HỌC TỐT............
Tìm x, biết:
\(\dfrac{2}{\left(x-1\right)\left(x-3\right)}+\dfrac{5}{\left(x-3\right)\left(x-8\right)}+\dfrac{12}{\left(x-8\right)\left(x-20\right)}-\dfrac{1}{x-20}=\dfrac{-1}{4}\)
Tìm STN x biết rằng:
a)\(720:[41-\left(2x-5\right)]=2^3\cdot5\)
b)\(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+100\right)=5+50\)
d)\(\left(x+3\right)^{10}=\left(x-3\right)^{17}\)
Bài 1; Tìm x, biết:
a) \(\text{2. |4 - x| = |-8|}\)
b) \(\left(x-1^2\right)=0\)
c) \(x\left(x-1\right)=0\)
d) \(\left(x+1\right)\left(x-2\right)=0\)
Tìm x
a, \(311-x+82=46+\left(x-21\right)\)
b,\(-\left(x-3+85\right)=\left(x+70-71\right)-5\)
c,\(-2\left(x+6\right)+6\left(x-10\right)=8\)
d,\(\left|x\right|=41\)
e, \(\left|-8\right|.\left|x\right|=\left|-56\right|\)
f,\(3.\left|x-2\right|+2x=19\) với \(x\) \(\ge\) 2
Giúp hộ đi ạ, cảm ơn.
1)tìm x\(\in\)Q biết:
a)\(\left(5\cdot x+1\right)^2=\dfrac{36}{49}\)
2)tìm x,y biết:
a)\(x^2+\left(y-\dfrac{1}{10}\right)^4=0\)
b)\(\left(\dfrac{1}{2}x-5\right)^{20}+\left(y^2-\dfrac{1}{4}\right)^{40}\le0\)
Tìm \(x,y\in Z\) biết \(\left(x+5\right)^2.\left(y-2\right)=8\)
Tìm x biết :
a) \(x.\left(x-1\right)-\left(x-1\right)^2\)
b) |x+1|+|x+2|+|x+7|=5x-10
Tìm số nguyên x biết :\(\left(x+1\right)\left(x+2\right)\left(x+3\right)...\left(x+100\right)\)
