\(\dfrac{4}{7}\)+\(\dfrac{5}{9}\): x = \(\dfrac{1}{5}\)
\(\dfrac{5}{9}\):x = \(\dfrac{1}{5}\)- \(\dfrac{4}{7}\)
\(\dfrac{5}{9}\): x = \(\dfrac{-13}{35}\)
x= \(\dfrac{5}{9}\):( \(\dfrac{-13}{35}\))
x = \(\dfrac{-175}{117}\)
Vậy x = \(\dfrac{-175}{117}\)
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\(\dfrac{4}{7}+\dfrac{5}{9}:x=\dfrac{1}{5}\)
\(\dfrac{5}{9}:x=\dfrac{1}{5}-\dfrac{4}{7}\)
\(\dfrac{5}{9}:x=\dfrac{-13}{35}\)
\(x=\dfrac{5}{9}:\dfrac{-13}{35}\)
\(x=\dfrac{-175}{117}\)