Bài 2: Cộng, trừ số hữu tỉ
Các câu hỏi tương tự
12 tháng 9 2021 lúc 14:54
1. Tìm x
\(2\dfrac{1}{2}-x+\dfrac{4}{5}=\dfrac{2}{3}-\left(-\dfrac{4}{7}\right)\)
12 tháng 9 2021 lúc 15:08
1.Tìm x
a) \(1\dfrac{4}{5}=-0,15-x\)
b) \(-\dfrac{4}{7}-x=\dfrac{3}{5}-2x\)
c) \(\left(\dfrac{3}{8}-\dfrac{1}{5}\right)+\left(\dfrac{5}{8}-x\right)=\dfrac{1}{5}\)
Tìm x biết:
a) \(x+\dfrac{1}{3}=\dfrac{3}{4}\) ; b) \(x-\dfrac{2}{5}=\dfrac{5}{7};\)
c) \(-x-\dfrac{2}{3}=-\dfrac{6}{7}\) ; d) \(\dfrac{4}{7}-x=\dfrac{1}{3}\)
a) /-4,1/ + 1,8+ /-3,5/ -/-4,1/-/-1,8/
b) /\(\dfrac{2}{5}\)/ - /-0,2/ \(\cdot\)/-7/
c) (-15) : /-3/ +/0,5/
giúp mk nha chiều đi học rùi
chú ý :
// là trị tuyệt đối nha
29 tháng 6 2021 lúc 12:31
e) \(\dfrac{3}{3x}-\dfrac{3}{12}=\dfrac{4}{5}-\left(\dfrac{7}{x}-2\right)\)
f) \(\dfrac{1}{x-1}+\dfrac{-2}{3}\left(\dfrac{3}{4}-\dfrac{6}{5}\right)=\dfrac{5}{2-2x}\)
a)2x.(x-\(\dfrac{1}{7}\) ) =0
b) \(\dfrac{3}{4}+\dfrac{1}{4}:x=\dfrac{2}{5}\)
c) \(4\dfrac{5}{9}:2\dfrac{5}{18}-7< x< \left(3\dfrac{1}{5}:3,2+4,5.1\dfrac{31}{45}\right)\)
Tim x, y biet:
a) \(x-\dfrac{3}{5}=\dfrac{3}{5}\)
b) \(\left|x\right|-\dfrac{4}{5}=\dfrac{2}{5}\)
c) \(\dfrac{x}{-5}=\dfrac{24}{15}\)
d) \(\dfrac{X}{4}=\dfrac{Y}{5}\)va \(x-y=21\)
GIUP MK T ^ T
29 tháng 6 2021 lúc 12:58
g) 3-dfrac{2}{2x-3}dfrac{2}{5}dfrac{2}{9-6x}-dfrac{3}{2}h) dfrac{x}{2}-dfrac{1}{x}dfrac{1}{12}i) x^2-dfrac{7}{6}x+dfrac{1}{3}0k) dfrac{13}{x-1}+dfrac{5}{2x-2}-dfrac{6}{3x-3}m) left(dfrac{3}{2}-dfrac{2}{-5}right):x-dfrac{1}{2}dfrac{3}{2}n) left(dfrac{3}{2}-dfrac{5}{11}-dfrac{3}{13}right)left(2x-2right)left(-dfrac{3}{4}+dfrac{5}{22}+dfrac{3}{26}right)
Đọc tiếp
g) \(3-\dfrac{2}{2x-3}=\dfrac{2}{5}=\dfrac{2}{9-6x}-\dfrac{3}{2}\)
h) \(\dfrac{x}{2}-\dfrac{1}{x}=\dfrac{1}{12}\)
i) \(x^2-\dfrac{7}{6}x+\dfrac{1}{3}=0\)
k) \(\dfrac{13}{x-1}+\dfrac{5}{2x-2}-\dfrac{6}{3x-3}\)
m) \(\left(\dfrac{3}{2}-\dfrac{2}{-5}\right):x-\dfrac{1}{2}=\dfrac{3}{2}\)
n) \(\left(\dfrac{3}{2}-\dfrac{5}{11}-\dfrac{3}{13}\right)\left(2x-2\right)=\left(-\dfrac{3}{4}+\dfrac{5}{22}+\dfrac{3}{26}\right)\)
bài 1 :
a)dfrac{3}{7} + ( -dfrac{5}{2} ) + ( dfrac{-3}{5} ) b) ( -dfrac{4}{3} ) + (-dfrac{2}{5} ) + (- dfrac{3}{2} )
c) dfrac{4}{5}- ( dfrac{-2}{7} ) - ( dfrac{7}{10} ) d ) dfrac{2}{3} - [(-dfrac{4}{7} ) - ( dfrac{1}{2} + dfrac{3}{8} )]
bài 2 : tìm x , biêt
a) x + dfrac{1}{3} dfrac{3}{4} ;...
Đọc tiếp
bài 1 :
a)\(\dfrac{3}{7}\) + ( -\(\dfrac{5}{2}\) ) + ( \(\dfrac{-3}{5}\) ) b) ( -\(\dfrac{4}{3}\) ) + (-\(\dfrac{2}{5}\) ) + (- \(\dfrac{3}{2}\) )
c) \(\dfrac{4}{5}\)- ( \(\dfrac{-2}{7}\) ) - ( \(\dfrac{7}{10}\) ) d ) \(\dfrac{2}{3}\) - [(-\(\dfrac{4}{7}\) ) - ( \(\dfrac{1}{2}\) + \(\dfrac{3}{8}\) )]
bài 2 : tìm x , biêt
a) x + \(\dfrac{1}{3}\) = \(\dfrac{3}{4}\) ; b) x- \(\dfrac{2}{5}\) = \(\dfrac{5}{7}\)
c) -x - \(\dfrac{2}{3}\) = - \(\dfrac{6}{7}\) d) \(\dfrac{4}{7}\) -x = \(\dfrac{1}{3}\)
( mai nộp bài rôi ai giúp vs )