a, | x| =0,37
=> x= cộng trừ 0,37
b, \(\dfrac{x}{169}\)= \(\dfrac{104}{x}\)
=> x.x = 169.104
=>x2=17576
=>x=\(26\sqrt{26}\)
c,\(\dfrac{x+9}{15}\)=\(\dfrac{3}{5}\)
=>(x+9).5= 15.3
=>5x+45 =45
=>5x=0
=>x=0
Chúc bạn học tốt 
a/ \(\left|x\right|=0,37\Rightarrow\left[{}\begin{matrix}x=0,37\\x=-0,37\end{matrix}\right.\)
Vậy...........
b/ \(\dfrac{x}{169}=\dfrac{104}{x}\Rightarrow x^2=104\cdot169=17576\)
\(\Rightarrow\left[{}\begin{matrix}x=\sqrt{17576}\\x=-\sqrt{17578}\end{matrix}\right.\)
Vậy.........
c/ \(\dfrac{x+9}{15}=\dfrac{3}{5}\Rightarrow5\left(x+9\right)=3\cdot15\)
\(\Rightarrow5x+45=45\)
\(\Rightarrow5x=0\Rightarrow x=0\)
Vậy..........
a) Trị tuyệt đối?
\(\left|x\right|=0,37\Rightarrow\left\{{}\begin{matrix}x=-0,37\\x=0,37\end{matrix}\right.\)
b) \(\dfrac{x}{169}=\dfrac{104}{x}\Rightarrow x^2=169.104=17576\)
\(\Rightarrow\left[{}\begin{matrix}x=\sqrt{17576}=26\sqrt{26}\\x=-\sqrt{17576}=-26\sqrt{26}\end{matrix}\right.\)
c) \(\dfrac{x+9}{15}=\dfrac{3}{5}\Rightarrow5\left(x+9\right)=45\)
\(\Rightarrow x+9=9\Rightarrow x=0\)
\(\left|x\right|=0,37\)
\(\Leftrightarrow x=0,37\)
\(\Leftrightarrow x=-0,37\)
\(\dfrac{x}{169}=\dfrac{104}{x}\)
\(x^2=169.104\)
\(x^2=17576\)
\(\Leftrightarrow x=\sqrt{17576}\)
\(\Leftrightarrow x=\sqrt{-17576}\)
\(\dfrac{x+9}{15}=\dfrac{3}{5}\)
\(\Leftrightarrow\dfrac{x+9}{15}=\dfrac{9}{15}\)
\(\Leftrightarrow x+9=9\)
\(\Leftrightarrow x=0\)
a) \(\left|x\right|=0,37\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0,69\\x=-0,69\end{matrix}\right.\)
Vậy \(x_1=0,69;x_2=-0,69\)
b) \(\dfrac{x}{169}=\dfrac{104}{x}\)
\(\Leftrightarrow x\cdot x=104\cdot169\)
\(\Leftrightarrow x^2=17576\)
\(\Leftrightarrow x=26\sqrt{26}\)
Vậy \(x=26\sqrt{26}\)
c) \(\dfrac{x+9}{15}=\dfrac{3}{5}\)
\(\Leftrightarrow x+9\cdot5=15\cdot3\)
\(\Leftrightarrow x+9\cdot5=45\)
\(\Leftrightarrow x+45=45\)
\(\Leftrightarrow x=0\)
Vậy \(x=0\)
