Question

Tìm x biết

a)\(\dfrac{-2}{3}\): x + \(\dfrac{5}{8}\) = \(\dfrac{-7}{12}\) b) ( \(\dfrac{1}{5}\) - \(\dfrac{3}{2}\) χ )\(^2\) = \(\dfrac{9}{4}\)

Answer 1

a) \(\dfrac{-2}{3}:x+\dfrac{5}{8}=\dfrac{-7}{12}\) b)\(\left(\dfrac{1}{5}-\dfrac{3}{2}x\right)^2=\dfrac{9}{4}\)

=> \(\dfrac{-2}{3}:x=\dfrac{-7}{12}-\dfrac{5}{8}=\dfrac{-29}{24}\) => \(\left(\dfrac{1}{5}-\dfrac{3}{2}x\right)^2=\left(\dfrac{3}{2}\right)^2\)

=> \(x=\dfrac{-2}{3}:\dfrac{-29}{24}\) => \(\dfrac{1}{5}-\dfrac{3}{2}x=\dfrac{3}{2}\)

=> \(x=\dfrac{-2}{3}.\dfrac{-24}{29}=\dfrac{16}{29}\) => \(\dfrac{3}{2}x=\dfrac{1}{5}-\dfrac{3}{2}\)

=> \(\dfrac{3}{2}x=\dfrac{-13}{10}\)

=> \(x=\dfrac{-13}{10}:\dfrac{3}{2}\)

=> \(x=\dfrac{-13}{10}.\dfrac{2}{3}=\dfrac{-13}{15}\)