Question

Tìm x biết :

a, (x-2)²+(y-3)²=0

b,5^(x-2).(x+3)=1

giúp mk vs giải ngắn gọn thôi nhé

CẢM ƠN NHIỀU

 

Answer 1

a)

(x-2)²\(\ge\))

(y-3)²\(\ge\)0

=> (x-2)²=(y-3)²=0

=>\(\begin{cases}x-2=0\\y-3=0\end{cases}\Rightarrowy=3}}\)

b)

để 5^(x-2)(x+3)=1

=> (x-2)(x+3)=0

=> \(\left[\begin{array}{nghiempt}x-2=0\\x+3=0\end{cases}\Rightarrow\left[\begin{array}{nghiempt}x=2\\x=-3\end{array}\right.}\)

Answer 2

a)\(\left(x+2\right)^2+\left(y-3\right)^2=0\)

\(\Leftrightarrow\begin{cases}x+2=0\\y-3=0\end{cases}\)\(\Leftrightarrow\begin{cases}x=-2\\y=3\end{cases}\)

Vậy x=-2 ; y=3

Answer 3

b)\(5^{\left(x-2\right)\left(x+3\right)}=1\)

\(\Leftrightarrow\left(x-2\right)\left(x-3\right)=0\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x-2=0\\x-3=0\end{array}\right.\) \(\Leftrightarrow\left[\begin{array}{nghiempt}x=2\\x=3\end{array}\right.\)