Question

Tìm x biết:

a, \(\left(x+1\right)^2\)=64

b, \(2^{x+1}\)=16

c, \(3^{x+1}\)=\(9^x\)

d, \(2^{3x+2}\)= \(4^{x+5}\)

e,\(3^{2x-1}\)=243

f,\(\left(x-\dfrac{1}{2}\right)^3\)=\(\dfrac{1}{27}\)

Giúp e vs ạ! Em đang cần gấp!Tks

Answer 1

a) x + 1 = 8 => x=7

b) x+1=4 => x=3
c) x+1=2 => x=1
d) 3x + 2 =2(x+ 5 )
3x - 2x = -2 + 10
x = 8

e) 2x - 1 = 5 (vì 243=3⁵)

=> x = 3

f) x - 1/2 = 1/3

=> x = 5/6

Chỗ nào k hiểu nói mình nhé

Answer 2

a/ (x+1)^2=64

=>(x+1)^2= 8^2

=>x+1 = 8

=>x = 8-1 = 7

b/2^x+1 = 16

=> 2^ x+1 = 2^4

=> x+1 = 4

=> x = 3

e/3^2x-1= 243

=>3^2x-1 = 3^5

=>2x-1 = 5

=>2x = 6

=>x =3