Question

Tìm x biết:

a, 4^x = 2^x+1

b, (x-1)⁴= 16

c, 1+3+5+...+99=(x-2)²

d, (19x+2.5²) :14= (13-8)² -4²

e, 2.3^x =10.3¹² +8.27⁴

g, 3+2^x-1=24-[ 4²-(2²-1)]

h, 720:[41-(2x-5)]=2³.5

i, 92.4-27= x+350/x +315

k, (x+1)+(x+2)+..+(x+100)=5750

Giúp mình nha mn!

Answer 1

k,(x + 1) + (x + 2) + (x + 3) + .... + (x + 100) = 5750

=> 100x + (1 + 2 + 3 + ... + 100) = 5750

=> 100x + 5050 = 5750

=> 100x = 5750 - 5050

=> 100x = 700

=> x = 700 : 100

=> x = 7

Answer 2

i,92.4 - 27 = (x + 350) : x + 315

=> 1 + 350 : x + 315 = 341

=> 350 : x = 341 - 316 = 25

-> x = 350: 25 = 14

Answer 3

h,720 : (41 - (2 x - 51) = 2³.5

=> 41 - (2 x -51) = 720 : 40 = 18

=> 2x = 41 - 18 + 51 = 74

=> x = 74 : 2 = 37

Answer 4

Toán lớp 6

g,3+2^x-1 =24 - [4²-(2²-1)]

3+2^x-1 =24 - [4²-(4-1)

3+2^x-1 =24 - [16-3]

3+2^x-1 =24 - 13

3+2^x-1 =11

2^x-1 =11-3

2^x-1 =8

2^x-1 =2³

x-1 =3

x= 3+1

x=4

Answer 5

e,2.3^x=10.3¹²+8.27⁴

=>2.3^x=10.3¹²+8.3¹²

=>2.3^x=18.3¹²

=>2.3^x=2.3².3¹²

=>2.3^x=2.3¹⁴

=>3^x=3¹⁴

=>x=14

vậy x=14

Answer 6

Ta thấy:QLC là 2.

=>SSH là:(99-1):2+1=50(số)

=>Tổng là:(1+99).50:2=2500

Ta có:2500=(x-2)²=50²=(-50)²

=>x-2=50 hoặc x-2=-50

x=52 x=-48

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