Question

Tìm x biết:

a, (1- 52/53)+(105/106-1)+(158/159-1)=|x|/318

Answer 1

=> \(\frac{1}{53}\)+ \(\frac{-1}{106}\)+\(\frac{-1}{159}\)= \(\frac{\left|x\right|}{318}\)

=> \(\frac{1}{318}\)= \(\frac{\left|x\right|}{318}\)

=> x thuộc {1; -1}

Answer 2

\(\left(1-\frac{52}{53}\right)+\left(\frac{105}{106}-1\right)+\left(\frac{158}{159}-1\right)=\frac{\left|x\right|}{318}\)

\(\Rightarrow\frac{1}{53}+\frac{-1}{106}+\frac{-1}{159}=\frac{\left|x\right|}{318}\)

\(\Rightarrow\frac{1}{318}=\frac{\left|x\right|}{318}\)

\(\Rightarrow\left|x\right|=1\)

\(\Rightarrow x=\pm1\)

Vậy..............................