/5x-4/=/x+2/
5x-4=+-(x+2)
5x-4=x+2
5x-x=2+4
4x=6
x=3/2
+5x-4=-x-2
5x+x=-2+4
6x=2
x=1/3
Mình không chắc đâu
/5x-4/=/x+2/
TH1:5x-4=x+2
4+2=5x-x
6=4x
=>x=1,5
TH2:5x-4=-x+2
4+2=5x+x
6=6x
=>x=1
TH3:-5x-4=x+2
4+2=-5x-x
6=-6x
=>x=-1
Vậy x\(\in\)\(\left\{-1;1;1,5\right\}\)