53-5(x-3)=38
5(x-3)=53-38
5(x-3)=15
x-3=15:5
x-3=3
x=3-3
x=0
Vậy x=0
53-5(x-3)=38
53-5x+15=38
-5x=38-53-15
-5x=-30
x=\(\dfrac{-30}{-5}\)=\(\dfrac{30}{5}\)=6
vậy x =6
53 - 5( x-3 ) = 38
53 - 5x - 15 = 38
5x - 15 = 53-38
5x - 15 = 15
5x = 15 - 15
5x = 0
=> x = 0
\(53-5\left(x-3\right)=38\)
\(=5\left(x-3\right)=53-38\)
\(=5\left(x-3\right)=15\)
\(x-3=15:5\)
\(x-3=3\)
\(x=3+3\)
\(x=6\)