\(\dfrac{5}{2}x-\dfrac{1}{3}x+2=\dfrac{3}{2}\)
\(\Rightarrow x\left(\dfrac{5}{2}-\dfrac{1}{3}\right)+2=\dfrac{3}{2}\)
\(\Rightarrow x\left(\dfrac{15}{6}-\dfrac{2}{6}\right)+2=\dfrac{3}{2}\)
\(\Rightarrow x.\dfrac{15-2}{6}+2=\dfrac{3}{2}\)
\(\Rightarrow\dfrac{13}{6}x+2=\dfrac{3}{2}\)
\(\Rightarrow\dfrac{13}{6}x=\dfrac{3}{2}-2\)
\(\Rightarrow\dfrac{13}{6}x=\dfrac{3}{2}-\dfrac{4}{2}\)
\(\Rightarrow\dfrac{13}{6}x=\dfrac{3-4}{2}\)
\(\Rightarrow\dfrac{13}{6}x=\dfrac{-1}{2}\)
\(\Rightarrow x=\dfrac{-1}{2}:\dfrac{13}{6}\)
\(\Rightarrow x=\dfrac{-1}{2}.\dfrac{6}{13}\)
\(\Rightarrow x=\dfrac{-1.6}{2.13}\)
\(\Rightarrow x=\dfrac{-6}{26}\)
\(\Rightarrow x=\dfrac{-3}{13}\)
Vậy \(x=\dfrac{-3}{13}\)