\(4x^2-6x=0\)
\(\Rightarrow2x.\left(2x-3\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}2x=0\\2x-3=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0:2\\2x=3\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=3:2\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=\frac{3}{2}\end{matrix}\right.\)
Vậy \(x\in\left\{0;\frac{3}{2}\right\}.\)
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