\(-4x\left(x-5\right)-2x\left(8-2x\right)=-3\)
⇔ \(-4x^2+20x-16x+4x^2=-3\)
⇔ \(4x=-3\)
\(\text{⇔}x=-\dfrac{3}{4}\)
KL........
\(-4x\left(x-5\right)-2x\left(8-2x\right)=-3< =>-4x\left(x-5\right)-4x\left(4-x\right)=-3< =>-4x\left(x-5+4-x\right)=-3< =>x=-\dfrac{3}{4}\)