các bn giải hộ mik nka, mik đag cần gấp câu hỏi này, cảm ơn trước nka
\(\left|3x-1\right|-2=3\)
\(\left|3x-1\right|=3+2\)
\(\left|3x-1\right|=5\)
\(\Leftrightarrow\left[{}\begin{matrix}3x-1=5\\3x-1=-5\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}3x=6\\3x=-4\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{-4}{3}\end{matrix}\right.\) \(\left(TM\right)\)
Vậy \(x\in\left\{2;\dfrac{-4}{3}\right\}\) là giá trị cần tìm
|3x-1|-2=3
=> |3x-1|=5
=> 3x-1\(\in\){5;-5}
=> 3x\(\in\){6;-4}
=> x\(\in\){2;1,3}
Vậy x\(\in\){2;1,3}.
|3x-1|-2=3
|3x-1| =3+2
|3x-1| =5
\(\Rightarrow\left|3\text{x}-1\right|=+5ho\text{ặc}-5\)
TH1:3x-1=5 TH2:3x-1=-5
3x =5+1 3x =-5+1
3x =6 3x =-4
x =6:3 x =-4:3
x =2 x =\(\dfrac{-4}{3}\)
Vậy x=2 hoặc x=\(\dfrac{-4}{3}\)
\(\left|3x-1\right|-2=3\)
\(\left|3x-1\right|=5\)
\(\Rightarrow3x-1\in\left\{-5;5\right\}\)
\(+)3x-1=-5\)
\(3x=-5+1\)
\(3x=-4\)
\(x=\dfrac{-4}{3}\)(loại)
\(+)3x-1=5\)
\(3x=6\)
\(x=2\)(TM)
Vậy x=2
