\(3+2^{x-1}=24-\left[4^2-\left(2^2-1\right)\right]\)
\(\Leftrightarrow3+2^{x-1}=24-\left(16-3\right)\)
\(\Leftrightarrow2^{x-1}=24-13-3\)
\(\Leftrightarrow2^{x-1}=8\)
\(\Leftrightarrow2^{x-1}=2^3\)
\(\Leftrightarrow x-1=3\)
\(\Leftrightarrow x=4\)
Vậy x = 4