\(2x\left(3x+1\right)+3x\left(4-2x\right)=7\)
\(\Rightarrow6x^2+2x+12x-6x^2=7\)
\(\Rightarrow\left(6x^2-6x^2\right)+\left(2x+12x\right)=7\)
\(\Rightarrow14x=7\)
\(\Rightarrow x=\dfrac{1}{2}\)
ta có:
2x(3x+1)+3x(4-2x)=7
<=>6(x^2)+2x+12x+6(x^2)=7
<=>[6(x^2)-6(x^2)]+(2x+12x)=7
<=>0+[x(2+12)]=7
<=>14x=7
<=>x=1/2
like mình với nhé bạn