\(\dfrac{1}{5.8}+\dfrac{1}{8.11}+\dfrac{1}{11.14}+...+\dfrac{1}{x\left(x+3\right)}=\dfrac{101}{1540}\)
Bài 3: Tìm x:
a) \(\dfrac{1}{5.8}\)+\(\dfrac{1}{8.11}\)+\(\dfrac{1}{11.14}\)+......+\(\dfrac{1}{x\left(x+3\right)}\)= \(\dfrac{101}{1540}\)
b) 1+ \(\dfrac{1}{3}\)+ \(\dfrac{1}{6}\)+\(\dfrac{1}{10}\)+......+ \(\dfrac{1}{x\left(x+1\right):2}\)=1\(\dfrac{1991}{1993}\)
Ai biết làm bài này thì giúp mik nhé!
mik đang cần gấp
Cảm ơn nhiều!♥
Câu hỏi today là a, \(\dfrac{1}{5\cdot8}+\dfrac{1}{8\cdot11}+...+\dfrac{1}{x+\left(x+1\right)}=\dfrac{101}{1540}\)
b,\(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+...+\dfrac{1}{x+\left(x+1\right)}=\dfrac{2020}{2021}\)
Chúc các bn học tốt ❤
Tìm x, biết rằng:
a, \(\dfrac{1}{5\cdot8}\) + \(\dfrac{1}{8\cdot11}\) + \(\dfrac{1}{11\cdot14}\) + ... + \(\dfrac{1}{x\left(x+3\right)}\) = \(\dfrac{101}{1540}\)
b, 1+\(\dfrac{1}{3}\) + \(\dfrac{1}{6}\) + \(\dfrac{1}{10}\) + ... + \(\dfrac{1}{x\left(x+1\right)\div2}\) = \(1\dfrac{1991}{1993}\)
\(\frac{1}{5.8}+\frac{1}{8.11}+......+\frac{1}{302.305}\)
Chứng tỏ: \(\frac{3}{2.5}+\frac{3}{5.8}+\frac{3}{8.11}+...+\frac{3}{14.17}< \frac{1}{2}\)
Tính tổng x + y , biết :
( x + 1 ) . ( y + 1 ) = 101
1. tính
a) A=\(\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}\)
b) B=\(\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+...+\frac{1}{120}\)
c) C=\(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{99.101}\)
d) D=\(\frac{3}{2.5}+\frac{3}{5.8}+\frac{3}{8.11}+...+\frac{3}{92.98}\)
D = 1 x 2x 3+3 x 4 x 5+ ... +99 x 100 x 101
giai ho minh ti nhanh len ^-^