Câu hỏi của Phan Bảo Hân

Question

Tìm x, biết :

1/2.x + 2/3 = 1/3.x + 1/6

CHÚ Ý :  dấu gạch chéo thay cho dấu gạch phân số nhé

Edogawa Conan · Accepted Answer

=> $\dfrac{1}{2}.x-\dfrac{1}{3}.x=\dfrac{1}{6}-\dfrac{2}{3}$

$x.\left(\dfrac{1}{2}-\dfrac{1}{3}\right)=\dfrac{1}{6}+\dfrac{-4}{6}$

$x.\left(\dfrac{3}{6}+\dfrac{-2}{6}\right)=\dfrac{-1}{2}$

$x.\dfrac{1}{6}=\dfrac{-1}{2}$

$x=\dfrac{-1}{2}:\dfrac{1}{6}$

$x=\dfrac{-1}{2}.6$

$x=-3$

Vậy x= -3Câu trả lời: => $\dfrac{1}{2}.x-\dfrac{1}{3}.x=\dfrac{1}{6}-\dfrac{2}{3}$

$x.\left(\dfrac{1}{2}-\dfrac{1}{3}\right)=\dfrac{1}{6}+\dfrac{-4}{6}$

$x.\left(\dfrac{3}{6}+\dfrac{-2}{6}\right)=\dfrac{-1}{2}$

$x.\dfrac{1}{6}=\dfrac{-1}{2}$

$x=\dfrac{-1}{2}:\dfrac{1}{6}$

$x=\dfrac{-1}{2}.6$

$x=-3$

Vậy x= -3

Nguyễn Lưu Vũ Quang · Answer

$\dfrac{1}{2}x+\dfrac{2}{3}=\dfrac{1}{3}x+\dfrac{1}{6}$

$\dfrac{1}{2}x-\dfrac{1}{3}x=\dfrac{1}{6}-\dfrac{2}{3}$

$x\left(\dfrac{1}{2}-\dfrac{1}{3}\right)=\dfrac{1}{6}-\dfrac{4}{6}$

$x\left(\dfrac{3}{6}-\dfrac{2}{6}\right)=-\dfrac{1}{2}$

$x\cdot\dfrac{1}{6}=-\dfrac{1}{2}$

$x=-\dfrac{1}{2}:\dfrac{1}{6}$

$x=-\dfrac{1}{2}\cdot6$

$x=-3$

Vậy $x=-3$.Câu trả lời: $\dfrac{1}{2}x+\dfrac{2}{3}=\dfrac{1}{3}x+\dfrac{1}{6}$

$\dfrac{1}{2}x-\dfrac{1}{3}x=\dfrac{1}{6}-\dfrac{2}{3}$

$x\left(\dfrac{1}{2}-\dfrac{1}{3}\right)=\dfrac{1}{6}-\dfrac{4}{6}$

$x\left(\dfrac{3}{6}-\dfrac{2}{6}\right)=-\dfrac{1}{2}$

$x\cdot\dfrac{1}{6}=-\dfrac{1}{2}$

$x=-\dfrac{1}{2}:\dfrac{1}{6}$

$x=-\dfrac{1}{2}\cdot6$

$x=-3$

Vậy $x=-3$.

Edogawa Conan · Answer

chuẩn cmnr đóCâu trả lời: chuẩn cmnr đó

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