\(\frac{x-1}{x+2}=\frac{x-2}{x+3}\)
\(\Leftrightarrow\)\(x-1.x+3=x+2.x-2\)
\(\Rightarrow\)\(\left(x-x\right).\left(1+3\right)=\left(x+x\right).\left(2-2\right)\)
\(0.4=2x.4\)
\(\Rightarrow0.0=2x.4\)
\(0=2x.4\)
\(\Leftrightarrow2x.4=0\)
\(2x=0:4\)
\(2x=0\)
\(x=0:2\)
\(\Rightarrow x=0\)
Vậy x=0
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