d) \(\frac{x-3}{x+2}=\frac{3}{4}\)
\(\Leftrightarrow\left(x-3\right).4=\left(x+2\right).3\)
\(\Leftrightarrow4x-12=3x+6\)
\(\Leftrightarrow4x-3x=6+12\)
\(\Leftrightarrow x=18\)
Vậy : \(x=18\)
b) \(\frac{9}{x-6}=\frac{x-6}{16}\)
\(\Leftrightarrow\left(x-6\right)^2=9.16=144\)
\(\Leftrightarrow\left[{}\begin{matrix}\left(x-6\right)^2=12^2\\\left(x-6\right)^2=\left(-12\right)^2\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x-6=12\\x-6=-12\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=18\\x=-6\end{matrix}\right.\)
Vậy : \(x\in\left\{18,-6\right\}\)
Mik lm nốt câu a, còn mấy câu kia bạn nguyễn văn đạt lm r