a) \(\frac{1}{3}x^2=\frac{1}{2}x\)
\(\Leftrightarrow\frac{1}{3}x^2-\frac{1}{2}x=0\)
\(\Leftrightarrow x\left(\frac{1}{3}x-\frac{1}{2}\right)=0\)
\(\Leftrightarrow\left[\begin{matrix}x=0\\\frac{1}{3}x-\frac{1}{2}=0\end{matrix}\right.\Leftrightarrow\left[\begin{matrix}x=0\\\frac{1}{3}x=\frac{1}{2}\end{matrix}\right.\Leftrightarrow\left[\begin{matrix}x=0\\x=\frac{3}{2}\end{matrix}\right.\)
Vậy: \(x=0;\frac{3}{2}\)
b) 32.2x+2=272
\(\Leftrightarrow\)32.2x+2=\(\left(3^3\right)^2\)
\(\Leftrightarrow\)32.2x+2=36
\(\Leftrightarrow\)2x+2=36:32
\(\Leftrightarrow\)2x+2=34
\(\Leftrightarrow\)2x+2=81
\(\Leftrightarrow\)2x=79
\(\Leftrightarrow\)x=\(\frac{79}{2}\)
