\(3x+3x+1+3x+2=117\)
\(\Rightarrow3x+3x+3x=117-1-2\)
\(\Rightarrow3x+3x+3x=114\)
\(\Rightarrow x.\left(3+3+3\right)=114\)
\(\Rightarrow x.9=114\)
\(\Rightarrow x=\dfrac{38}{3}\)
Vậy \(x=\dfrac{38}{3}\)
=> 3x+3x+3x+1+2=117
=>9x+3=117
=>9x=117-3=114
=> x=\(\dfrac{114}{9}\)
\(3x+3x+1+3x+2=117\)
\(\Leftrightarrow9x=114\)
\(\Leftrightarrow x=\dfrac{38}{3}\)
3x+3x+1+3x+2=117
=> 3x+3x+3x+1+2=117
=> 9x+3=117
=> 9x= 114
=> x= 114/9
=> x = 8/3
3x+3x+1+3x+2 =117
3x.(1+2)=117
3x.3=117
3x=117:3
3x=39
x=39:3
x=13
\(3x+3x+1+3x+2=117\)
\(9x+3=117\)
\(9x=114\)
\(x=\dfrac{114}{9}=\dfrac{38}{3}\)
\(3x+3x+1+3x+2=117\)
\(9x+3=117\)
\(9x=114\)
\(x=\dfrac{114}{9}=\dfrac{38}{3}\)
