\(\Rightarrow\)\(3^{\left(x-2\right)\left(x-3\right)}\)=\(3^0\)
\(\Rightarrow\)(x-2)(x-3)=0
Để (x-2)(x-3)=0
\(\Rightarrow\)x-2=0 hoặc x-3=0
+)x-2=0
x=0+2
x=2
+)x-3=0
x=0+3
x=3
Vậy x=2 hoặc 3
Bài 2: Cộng, trừ số hữu tỉ
Các câu hỏi tương tự
tìm x , biết
a) 17/6- x( x-7/6)= 7/4
b) 3/35 - ( 3/5-x)= 2/7
tìm x thuộc Z , biết
3/4-5/6 < x/12 < 1 -( 2/3-1/4)
tìm x biết
a ) 2x-3=x + 1/2
b) 4x- ( x+ 1/2) = 2x - ( 1/2 - 5 )
tìm x: x-[17/2 - (-3/7 + 5/3)] = -1/3
Tìm x ϵ Z, biết:
1/2 - (1/3 + 3/4) ≤ x ≤ 1/24 - (1/8 - 1/3)
12 tháng 9 2021 lúc 14:54
1. Tìm x
\(2\dfrac{1}{2}-x+\dfrac{4}{5}=\dfrac{2}{3}-\left(-\dfrac{4}{7}\right)\)
29 tháng 6 2021 lúc 12:58
g) 3-dfrac{2}{2x-3}dfrac{2}{5}dfrac{2}{9-6x}-dfrac{3}{2}h) dfrac{x}{2}-dfrac{1}{x}dfrac{1}{12}i) x^2-dfrac{7}{6}x+dfrac{1}{3}0k) dfrac{13}{x-1}+dfrac{5}{2x-2}-dfrac{6}{3x-3}m) left(dfrac{3}{2}-dfrac{2}{-5}right):x-dfrac{1}{2}dfrac{3}{2}n) left(dfrac{3}{2}-dfrac{5}{11}-dfrac{3}{13}right)left(2x-2right)left(-dfrac{3}{4}+dfrac{5}{22}+dfrac{3}{26}right)
Đọc tiếp
g) \(3-\dfrac{2}{2x-3}=\dfrac{2}{5}=\dfrac{2}{9-6x}-\dfrac{3}{2}\)
h) \(\dfrac{x}{2}-\dfrac{1}{x}=\dfrac{1}{12}\)
i) \(x^2-\dfrac{7}{6}x+\dfrac{1}{3}=0\)
k) \(\dfrac{13}{x-1}+\dfrac{5}{2x-2}-\dfrac{6}{3x-3}\)
m) \(\left(\dfrac{3}{2}-\dfrac{2}{-5}\right):x-\dfrac{1}{2}=\dfrac{3}{2}\)
n) \(\left(\dfrac{3}{2}-\dfrac{5}{11}-\dfrac{3}{13}\right)\left(2x-2\right)=\left(-\dfrac{3}{4}+\dfrac{5}{22}+\dfrac{3}{26}\right)\)
12 tháng 9 2021 lúc 14:47
1. Tìm x
\(-\dfrac{3}{5}-x=-0,75\)
\(\left(\dfrac{1}{2}.x-\dfrac{2}{3}\right)-\left(\dfrac{1}{3}.x-1\right)=\left(x-3\right)-\left(x-1\right)\)
Bài 1: Tìm x:
a) x - \(\frac{4}{5}=\frac{7}{10}-\frac{3}{4}\)
b)\(2\frac{1}{3}-x=\frac{-5}{9}+2x\)
c) \(\frac{x+3}{2016}+\frac{x+2}{2017}=\frac{x+1}{2018}+\frac{x}{2019}\)
d) \(\frac{1}{x\left(x+1\right)}+\frac{1}{\left(x+1\right)\left(x+2\right)}+\frac{1}{\left(x+2\right)\left(x+3\right)}-\frac{1}{x}=\frac{1}{2010}\)
12 tháng 9 2021 lúc 15:08
1.Tìm x
a) \(1\dfrac{4}{5}=-0,15-x\)
b) \(-\dfrac{4}{7}-x=\dfrac{3}{5}-2x\)
c) \(\left(\dfrac{3}{8}-\dfrac{1}{5}\right)+\left(\dfrac{5}{8}-x\right)=\dfrac{1}{5}\)
29 tháng 6 2021 lúc 13:21
h) \(\dfrac{x}{2}-\dfrac{1}{x}=\dfrac{1}{12}\)
i) \(x^2-\dfrac{7}{6}x+\dfrac{1}{3}=0\)
k) \(\dfrac{13}{x-1}+\dfrac{5}{2x-2}-\dfrac{6}{3x-3}\)