Question

tìm x

3(2x-1)-5(x-3)+6(3x-4)=24

trình bày hộ nhé

Answer 1

\(3\left(2x-1\right)-5\left(x-3\right)+6\left(3x-4\right)=24\)

\(\Leftrightarrow\) \(6x-3-5x+15+18x-24=24\)

\(\Leftrightarrow\) \(19x-12=24\Leftrightarrow19x=24+12=36\Leftrightarrow x=\dfrac{36}{19}\)

vậy \(x=\dfrac{36}{19}\)

Answer 2

\(3\left(2x-1\right)-5\left(x-3\right)+6\left(3x-4\right)=24\)

\(\Leftrightarrow6x-3-5x+15+18x-24-24=0\)

\(\Leftrightarrow19x-36=0\)

\(\Leftrightarrow19x=36\)

\(\Leftrightarrow x=\dfrac{36}{19}\)