Question

Tìm x:

3-(1/6-x).2/3=2/3

Answer 1

\(3-\left(\dfrac{1}{6}-x\right)\cdot\dfrac{2}{3}=\dfrac{2}{3}\)

\(\left(\dfrac{1}{6}-x\right)\cdot\dfrac{2}{3}=3-\dfrac{2}{3}\)

\(\left(\dfrac{1}{6}-x\right)\cdot\dfrac{2}{3}=\dfrac{9}{3}-\dfrac{2}{3}\)

\(\left(\dfrac{1}{6}-x\right)\cdot\dfrac{2}{3}=\dfrac{7}{3}\)

\(\dfrac{1}{6}-x=\dfrac{7}{3}:\dfrac{2}{3}\)

\(\dfrac{1}{6}-x=\dfrac{7}{3}\cdot\dfrac{3}{2}\)

\(\dfrac{1}{6}-x=\dfrac{7}{2}\)

\(x=\dfrac{1}{6}-\dfrac{7}{2}\)

\(x=\dfrac{1}{6}-\dfrac{21}{6}\)

\(x=\dfrac{-20}{6}\)

Vậy \(x=\dfrac{-20}{6}\).

Answer 2

\(3-\left(\dfrac{1}{6}-x\right)\cdot\dfrac{2}{3}=\dfrac{2}{3}\\ \left(\dfrac{1}{6}-x\right)\cdot\dfrac{2}{3}=3-\dfrac{2}{3}\\\left(\dfrac{1}{6}-x\right)\cdot\dfrac{2}{3}=\dfrac{9}{3}-\dfrac{2}{3}\\ \left(\dfrac{1}{6}-x\right)\cdot\dfrac{2}{3}=\dfrac{7}{3}\\ \dfrac{1}{6}-x=\dfrac{7}{3}:\dfrac{2}{3}\\ \dfrac{1}{6}-x=\dfrac{7}{3}\cdot\dfrac{3}{2}\\ \dfrac{1}{6}-x=\dfrac{7}{2}\\ x=\dfrac{1}{6}-\dfrac{7}{2}\\ x=\dfrac{1}{6}-\dfrac{21}{6}\\ x=\dfrac{-20}{6}\\ x=\dfrac{-10}{3}\)