=>(2x+3,5)=16/3:8/3=2
=>2x=-1,5
=>x=-0,75
\(\left(3\dfrac{1}{2}+2x\right)\times2\dfrac{2}{3}=5\dfrac{1}{3}\\ =>\left(\dfrac{7}{2}+2x\right)\times\dfrac{8}{3}=\dfrac{16}{3}\\ =>\dfrac{7}{2}+2x=\dfrac{16}{3}:\dfrac{8}{3}\\ =>\dfrac{7}{2}+2x=2\\ =>2x=2-\dfrac{7}{2}\\ =>2x=-\dfrac{3}{2}\\ =>x=-\dfrac{3}{2}:2\\ =>x=-\dfrac{3}{4}\)