Question

Tìm x:

2x² – 2 + (2x – 1)(3 – x) = 2

Answer 1

\(2x^2-2+\left(2x-1\right)\left(3-x\right)=2\)

\(\Rightarrow2x^2-2+6x-2x^2-3+x=2\)

\(\Rightarrow7x-5=2\)

⇒ 7x = 7

⇒ x = 1

Answer 2

\(2x^2-2+\left(2x-1\right)\left(3-x\right)=2\\ \Leftrightarrow2x^2-2+6x-2x^2+x-3=2\\ \Leftrightarrow7x=7\\ \Leftrightarrow x=1\)