2(x+1) +3(x+3)=-8
=>2x+2+3x+9 =-8
=>5x+11=-8
=>5x=-19
=>x=\(\dfrac{-19}{5}\)
Tìm x:
\(2\left(x-1\right)+3\left(x+3\right)=-8\)
\(\Leftrightarrow2x-2+3x+9=-8\)
\(\Leftrightarrow5x=-8+2-9\)
\(\Leftrightarrow5x=-15\)
\(\Leftrightarrow x=-3\)
Vậy \(x=-3\)
Ta có :
2(x-1) + 3(x+3) = -8
\(\Leftrightarrow\)2x-2 + 3x+9 = -8
\(\Leftrightarrow\) 5x + 7 = -8
\(\Leftrightarrow\) 5x = -15
\(\Leftrightarrow\) x = -3