Question

tìm x

0,2x - \(\dfrac{2}{3}\) . (x+1) = \(\dfrac{1}{3}\)

Answer 1

\(\dfrac{1}{5}x-\dfrac{2}{3}x-\dfrac{2}{3}-\dfrac{1}{3}=0\)

\(\Leftrightarrow\dfrac{-7}{15}x-1=0\)

\(\Leftrightarrow\dfrac{-7x}{15}=1\)

\(\Leftrightarrow x=\dfrac{-15}{7}\)

Answer 2

0,2x - \(\dfrac{2}{3}x\)- \(\dfrac{2}{3}\)=\(\dfrac{1}{3}\)

<=> \(\dfrac{-1,4}{3}\)x=1

<=> x = \(\dfrac{-3}{1,4}\)