a, x-47= 115 b, 146- x =401 -135= 86
x= 115=47 = 162 x=146- 86=60
a) \(\left(x-47\right)-115=0\)\(\Leftrightarrow x-47=115\)\(\Leftrightarrow x=47+115=162\).
b) \(315+\left(146-x\right)=401\)\(\Leftrightarrow146-x=401-315\)\(\Leftrightarrow146-x=86\)\(\Leftrightarrow x=146-86\)\(\Leftrightarrow x=60\).
a) Ta có: \(\left(x-47\right)-115=0\)
\(\Rightarrow x=115+47\)
\(\Rightarrow x=162\)
Vậy \(x=162\)
b) Ta có: \(315+\left(146-x\right)=401\)
\(\Rightarrow-x=401-315-146\)
\(\Rightarrow-x=-60\)
\(\Rightarrow x=60\)
Vậy \(x=60\)
\(a,\left(x-47\right)-115=0\\ x-47=0+115\\ x-47=115\\ x=115+47\\ x=162\)
\(b,315+\left(146-x\right)=401\\ 146-x=401-315\\ 146-x=86\\ x=146-86\\ x=60\)
Tìm số tự nhiên xx, biết :
a) (x−47)−115=0
\(\Leftrightarrow\) x - 47 = 0 + 115
\(\Leftrightarrow\) x -47 = 115
\(\Leftrightarrow\) x = 115 + 47
\(\Leftrightarrow\) x = 162
Vậy x = 162
b) 315+(146−x)=401
\(\Leftrightarrow\) 146 - x = 401 - 315
\(\Leftrightarrow\) 146 - x = 86
\(\Leftrightarrow\) x = 146 - 86
\(\Leftrightarrow\) x = 60
Vậy x = 60
Tìm số tự nhiên \(x\) biết :
a) \(\left(x-47\right)-115=0\)
\(x=0:15\)
\(x=0\)
\(x=0+47\)
\(x=47\)
b) \(315+\left(146-x\right)=401\)
\(x=401-315\)
\(x=86\)
\(x=146-86\)
\(x=60\)
a) ( x-47 )-115=0
x-47 = 0+115
x-47 = 115
x = 115+47
x = 162
b) 315+ ( 146-x )= 401
146-x = 401-315
146-x = 86
x = 146-86
x = 60
a,(x-47)-115=0
(x-47) =0+115
x-47 =115
x =115+37
x =162
