Câu hỏi của Angel Sunset

Question

Tìm số nguyên n biết n+2 là ước của 16

Help me ! Thank nhiều !!!!

Kyoko Rin · Accepted Answer

n=35Câu trả lời: n=35

Hoang Hung Quan · Answer

$n+2=Ư(16)$

$\RightarrowƯ\left(16\right)=\left\{1;2;4;8;16\right\}$

Ta có:

$n+2=1\Rightarrow n=1-2=-1$

$n+2=2\Rightarrow n=2-2=0$

$n+2=4\Rightarrow n=4-2=2$

$n+2=8\Rightarrow n=8-2=6$

$n+2=16\Rightarrow n=16-2=14$

$\Rightarrow n=\left\{-1;0;2;6;14\right\}$Câu trả lời: $n+2=Ư(16)$

$\RightarrowƯ\left(16\right)=\left\{1;2;4;8;16\right\}$

Ta có:

$n+2=1\Rightarrow n=1-2=-1$

$n+2=2\Rightarrow n=2-2=0$

$n+2=4\Rightarrow n=4-2=2$

$n+2=8\Rightarrow n=8-2=6$

$n+2=16\Rightarrow n=16-2=14$

$\Rightarrow n=\left\{-1;0;2;6;14\right\}$

Trần Hoàng Bảo Ngọc · Answer

n + 2 = Ư(16) => n + 2 $\in$Ư(16)

Ư(16) = { 1 ; 2 ; 4 ; 8 ; 16 }

TH1 :

n + 2 = 1

=> n = -1

TH2 :

n + 2 = 2

=> n = 0

TH3 :

n + 2 = 4

=> n = 2

TH4 :

n + 2 = 8

=> n = 6

TH5 :

n + 2 = 16

=> n = 14

Vậy n = -1 ; 0 ; 2 ; 6 ; 14Câu trả lời: n + 2 = Ư(16) => n + 2 $\in$Ư(16)