đặt p=\(\dfrac{7}{x}\) ( x ∈ Z và x ≠ 0)
theo bài ra: \(\dfrac{10}{13}\)< \(\dfrac{7}{x}\)< \(\dfrac{10}{11}\) ⇒ \(\dfrac{70}{91}< \dfrac{70}{10x}< \dfrac{70}{77}\)
suy ra: 91>10x>77 ⇒ x ∈ \(\left\{7;8;9\right\}\)
suy ra \(\dfrac{7}{x}=\dfrac{7}{7}\); \(\dfrac{7}{8};\dfrac{7}{9}\) hay p=\(\dfrac{7}{7};\dfrac{7}{8};\dfrac{7}{9}\)
vậy p= \(\dfrac{7}{7};\dfrac{7}{8};\dfrac{7}{9}\)
chúc bạn học tốt nha